(x^2-3x-28)/(x-1)=x

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Solution for (x^2-3x-28)/(x-1)=x equation: 



(x^2-3x-28)/(x-1)=x

We move all terms to the left:

(x^2-3x-28)/(x-1)-(x)=0



Domain of the equation: (x-1)!=0

We move all terms containing x to the left, all other terms to the right

x!=1

x∈R



We add all the numbers together, and all the variables

-1x+(x^2-3x-28)/(x-1)=0

We multiply all the terms by the denominator


-1x*(x-1)+(x^2-3x-28)=0

We multiply parentheses

-x^2+1x+(x^2-3x-28)=0

We get rid of parentheses

-x^2+x^2+1x-3x-28=0

We add all the numbers together, and all the variables

-2x-28=0

We move all terms containing x to the left, all other terms to the right

-2x=28

x=28/-2

x=-14

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